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PBTS model: derived POL "demonstration"

cason/pbts
Daniel Cason 3 years ago
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1 changed files with 27 additions and 7 deletions
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      spec/consensus/proposer-based-timestamp/pbts-sysmodel_002_draft.md

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spec/consensus/proposer-based-timestamp/pbts-sysmodel_002_draft.md View File

@ -208,9 +208,9 @@ If
Then, let `p` is a such correct process: Then, let `p` is a such correct process:
- `p` received a `PROPOSE` message of round `v.round`, and
- the `PROPOSE` message contained a proposal `(v, v.time, v.round)`, and
- `p` considered the proposal time `v.time` `timely`.
- `p` received a `PROPOSAL` message of round `v.round`, and
- the `PROPOSAL` message contained a proposal `(v, v.time, v.round)`, and
- `p` was in round `v.round` and evaluated the proposal time `v.time` as `timely`.
The existence of a such correct process `p` is guaranteed provided that the The existence of a such correct process `p` is guaranteed provided that the
voting power of Byzantine processes is bounded by `2f`. voting power of Byzantine processes is bounded by `2f`.
@ -220,7 +220,7 @@ voting power of Byzantine processes is bounded by `2f`.
The existence of `POL(v,r)` is a requirement for the decision of `v` at round The existence of `POL(v,r)` is a requirement for the decision of `v` at round
`r` of consensus. `r` of consensus.
At the same time, the Time-Validity property established that if `v` is decided
At the same time, the Time-Validity property establishes that if `v` is decided
then a timely proof-of-lock `POL(v,v.round)` must have been produced. then a timely proof-of-lock `POL(v,v.round)` must have been produced.
So, we need to demonstrate here that any valid `POL(v,r)` is either a timely So, we need to demonstrate here that any valid `POL(v,r)` is either a timely
@ -235,15 +235,35 @@ If
Then Then
- there is a valid `POL(v,v.round)` with `v.round <= r`,
- so a correct process considered the proposal for `v` `timely` at round `v.round`.
- there is a valid `POL(v,v.round)` with `v.round <= r` which is a timely proof-of-lock.
The above relation is trivially observed when `r = v.round`, as `POL(v,r)` must The above relation is trivially observed when `r = v.round`, as `POL(v,r)` must
be a timely proof-of-lock. be a timely proof-of-lock.
(Notice that, by the definition of `v.round`, we cannot have `r < v.round`).
Notice that we cannot have `r < v.round`, as `v.round` is defined as the first
round at which `v` was proposed.
For `r > v.round` we need to demonstrate that if there is a valid `POL(v,r)`, For `r > v.round` we need to demonstrate that if there is a valid `POL(v,r)`,
then a timely `POL(v,v.round)` was previously obtained. then a timely `POL(v,v.round)` was previously obtained.
We observe that a condition for observing a `POL(v,r)` is the proposer of round
`r` having broadcast a `PROPOSAL` message for `v`.
As `r > v.round`, we can affirm that `v` was not produced in round `r`.
So `v` was, by the protocol operation, the highest *valid value* known by the
proposer when it started the round.
A value `v` becomes a valid value when there is `POL(v,r')` with `r' < r'`.
Even though the proposer `p` can be incorrect, the fact of a `POL(v,r)` was
produced ensures that at least one correct process also observed a `POL(v,r')`.
> Considering the algorithm in the [arXiv paper][arXiv], `v` was proposed by
> the proposer `p` of round `r == round_p` because it has `validValue_p == v`.
> The `PROPOSAL` message of round `r` proposing `v`, in this case, has its
> `validRound` field set to `r' == validRound_p >= v.round`.
So, if there is a `POL(v,r)` with `r > v.round`, then there is a valid
`POL(v,r')` with `v.round <= r' < r'.
From this point, the reasoning becomes recursive: either `r' == v.round` and
`POL(v,r')` is a timely proof-of-lock, or there is another `POL(v,r'')` with
`r'' < r'`, recursively leading to the first scenario (as `r` necessarily
decreases at each recursive iteration).
### SAFETY ### SAFETY


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