python3: fix distutils path to package when using bytecodes

If there is only Python bytecodes, then
the __init__.py script will be concatenated, and
the __init__.pyc as well.

This is becase this bit `path = os.path.join(path, '__init__'+extension)`
is iterated twice.

This is a bug in Python3, also because we ship bytecodes
instead of source code [ with Python & Python3 ].
Python is not affected.

Reported-by: Mirko Vogt <mirko@nanl.de>
Signed-off-by: Alexandru Ardelean <ardeleanalex@gmail.com>

lang/python/python3/Makefile

@@ -14,7 +14,7 @@ PYTHON_VERSION:=$(PYTHON3_VERSION)
 PYTHON_VERSION_MICRO:=$(PYTHON3_VERSION_MICRO)
 
 PKG_NAME:=python3
-PKG_RELEASE:=2
+PKG_RELEASE:=3
 PKG_VERSION:=$(PYTHON_VERSION).$(PYTHON_VERSION_MICRO)
 
 PKG_SOURCE:=Python-$(PKG_VERSION).tar.xz

lang/python/python3/patches/008-fix-distutils-path-creation.patch

@@ -0,0 +1,16 @@
+diff --git a/Lib/imp.py b/Lib/imp.py
+index 781ff23..beeac70 100644
+--- a/Lib/imp.py
++++ b/Lib/imp.py
+@@ -203,8 +203,9 @@ def load_package(name, path):
+         extensions = (machinery.SOURCE_SUFFIXES[:] +
+                       machinery.BYTECODE_SUFFIXES[:])
+         for extension in extensions:
+-            path = os.path.join(path, '__init__'+extension)
+-            if os.path.exists(path):
++            init_path = os.path.join(path, '__init__'+extension)
++            if os.path.exists(init_path):
++                path = init_path
+                 break
+         else:
+             raise ValueError('{!r} is not a package'.format(path))